vin check digit
#1
Drifting
Thread Starter
vin check digit
Not sure if this has been discussed before, but I checked the math on mine, and yup, it's a 3....
"Check Digit: The Check Digit is located in a Vehicle Identification Number (VIN).
To determine the check digit (9th digit) of your car's Vehicle Identification Number, follow these steps:
•Take the VIN and re-assign any letters in the VIN with a set value (number) as follows:
A = 1, B = 2, C = 3, D = 4, E = 5, F = 6, G = 7, H = 8,
J = 1, K = 2, L = 3, M = 4, N = 5, O = 6, P = 7, R = 9,
S = 2, T = 3, U = 4, V = 5, W = 6, X = 7, Y = 8, Z = 9
Any numbers in the VIN remain the same (not replaced) and thus you have a 17 digit number.
•Multiply each of the 17 digits by a set "weight" (multiplier). The weight applied to each digit is as follows:
1st = 8, 2nd = 7, 3rd = 6, 4th = 5, 5th = 4, 6th = 3, 7th = 2, 8th = 10, 9th = 0 (check digit),
10th = 9, 11th = 8, 12th = 7, 13th = 6, 14th = 5, 15th = 4, 16th = 3, 17th = 2
After multiplying each VIN digit by the associated weight - add up the results of all 17 products. Then divide by 11 and
the remainder is your check digit.
•If the remainder is the digits 0 thru 9, then your Check Digit is the same numeric value. If the remainder is 10, then the check digit is 'X'.
Here's an example: VIN = 1G1BL52P7TR115520 (note '7' is the check digit)
VIN: 1 G 1 B L 5 2 P 7 T R 1 1 5 5 2 0
Assigned Values: 1 7 1 2 3 5 2 7 7 3 9 1 1 5 5 2 0
Multiplier: 8 7 6 5 4 3 2 10 0 9 8 7 6 5 4 3 2
Add the products: (1 X 8) + (7 X 7) + (1 X 6) ... (0 X 2) = 337
Divide 337 by 11 which gives you 30, and a remainder of 7 which is the same as the 9th digit of the VIN."
"Check Digit: The Check Digit is located in a Vehicle Identification Number (VIN).
To determine the check digit (9th digit) of your car's Vehicle Identification Number, follow these steps:
•Take the VIN and re-assign any letters in the VIN with a set value (number) as follows:
A = 1, B = 2, C = 3, D = 4, E = 5, F = 6, G = 7, H = 8,
J = 1, K = 2, L = 3, M = 4, N = 5, O = 6, P = 7, R = 9,
S = 2, T = 3, U = 4, V = 5, W = 6, X = 7, Y = 8, Z = 9
Any numbers in the VIN remain the same (not replaced) and thus you have a 17 digit number.
•Multiply each of the 17 digits by a set "weight" (multiplier). The weight applied to each digit is as follows:
1st = 8, 2nd = 7, 3rd = 6, 4th = 5, 5th = 4, 6th = 3, 7th = 2, 8th = 10, 9th = 0 (check digit),
10th = 9, 11th = 8, 12th = 7, 13th = 6, 14th = 5, 15th = 4, 16th = 3, 17th = 2
After multiplying each VIN digit by the associated weight - add up the results of all 17 products. Then divide by 11 and
the remainder is your check digit.
•If the remainder is the digits 0 thru 9, then your Check Digit is the same numeric value. If the remainder is 10, then the check digit is 'X'.
Here's an example: VIN = 1G1BL52P7TR115520 (note '7' is the check digit)
VIN: 1 G 1 B L 5 2 P 7 T R 1 1 5 5 2 0
Assigned Values: 1 7 1 2 3 5 2 7 7 3 9 1 1 5 5 2 0
Multiplier: 8 7 6 5 4 3 2 10 0 9 8 7 6 5 4 3 2
Add the products: (1 X 8) + (7 X 7) + (1 X 6) ... (0 X 2) = 337
Divide 337 by 11 which gives you 30, and a remainder of 7 which is the same as the 9th digit of the VIN."
#3
Drifting
Thread Starter
#4
Try putting the "incorrect one" in here !!!!
http://www.alton-moore.net/vin_calculation.html
Last edited by WVZR-1; 09-02-2015 at 10:29 PM.