HUMount Illumination Dimmer?
I have it hooked up to the HVAC Ilummination Dimmer hot lead, but when it is on full power it overpowers all, and if using the dash dimmer to get it to acceptable matching levels for the rest of the guages, then the rest of the dash/ gauges are almost off non visible.
do I need a inline dimmer, if so has anyone else experienced this and what dimmer switch did you use, any preferences ?
I found this , any one using it ?
[URL="http://www.oznium.com/inline-led-controller"URL]
All help appreciated
Thanks
Last edited by BACNBLK; Dec 29, 2012 at 02:08 PM.
You could just put a resistor on the + wire in series. Only problem is you need to take current measurement on LED and calculate what ohm resistor to get. I can help with calculations if you need it.
I will need it to be half as Bright as is now, it is the Mini Red LED they called it.
Let me know how I can test it or what to check?
Thanks!
Voltage (E) = Current (I) * Resistance (R)
Determine the resistance of the LED using the two numbers you know.
Total voltage drop for a circuit is equal to system voltage. Voltage drop across each load in a series circuit is proportional to the resistance of each load in the circuit. The resistance of each load is constant, so the LED's will always be at the resistance that you first calculate (voltage and current can change at each load). You can't really put meter leads across LED with it set to resistance, it doesn't quite work right.
If system is at 13v, I would guess 10v on LED would drop brightness enough but you may want to save a trip and get resistor for 8v also. Or just buy a bunch of small ones, or an adjustable pot, depends what your local Radio Shack has in stock.
For example:
If LED has measured 100 mA current at 13v... 13=.1*R so R(led)=130ohms (just an example, measure it to see what actual current is).
If you want the voltage at the LED's to be 10v you need a resistor that will drop voltage 3v before the LED. Since you know the 3v and 10v, and you now know R(led), you can figure out what ohm resistor to buy for the 3v drop.
R(resistor) / R(LED) = V (resistor) / V (LED) ..so.. R(r)/130ohm = 3v/10v ..so.. R(resistor) = 39ohms FOR THIS EXAMPLE
Measure current and voltage on LED and do the math









