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The human ear interprets sound on a logarithmic scale. An octave is a doubling of frequency. For instance, 60 Hz is a b flat. The next b flat up is 120 Hz, then 240 Hz, then 480 Hz, and so on. To find the difference between certain notes, use:
F = F0*2^(diff/12)
That's kind of cryptic, so I'll explain it. F0 is the original frequency. diff is the number of half-steps (on the western 12-note chromatic scale) that you want to move. So, if you want to know what the C below A440 is, you get:
F = 440*2^(-9/12)
F = 261.63 Hz
You can replace (diff/12) with the number of octaves you want to move. If you want to know what a half-octave below 35 Hz is, just use -1/2 there.
You can figure out how many octaves are between two different frequencies by using:
Octaves = log2(F/F0)
log2 means log base 2. I don't think I can do subscripts here. So if you have a low-pass first order filter that cuts off at 80 Hz and you want to find how much it attenuates 100 Hz signals, just do:
Octaves = log2(100/80)
then
dB = Octaves * -6dB/octave
I can't do that math on the crappy calculator program that windows has, but you get my point.
And yes, ported enclosures roll off at 12dB per octave.
There is no specific number of Hz in an octave. And octave represents a doubling of frequency. Hence 20 Hz in an octave above 10 Hz which is a 10 Hz change. But, 2000 Hz is an octave above 1000 Hz which is a 1000 Hz change.