Shark Bite Rear Coilovers





Last edited by Billysvette; Mar 13, 2008 at 05:41 PM.
A well setup stock suspension will do 90% of what 90% of the people on this board ask of it. This is simply something to look at.
And we know what those kinds of people are called.
BigBlockk
Later.....
The system above is truly independent but is that good? It offers no additional roll resistance, I'm not seeing a sway bar even.
I've been looking at the rockers and they seem to have a 3:2 ratio or thereabouts. What this does is, it gives a reduced shock & spring travel for a given wheel travel. This reduces shock efficiency and spring efficiency. You'll need a higher rate spring to control the suspension because of this ratio and your shock will need stiffer dampening and the shock will work over a shorter compression/extension range. Also, consider that spring rate is a load per inch of compression, this means that if the effective travel is reduced, the actual load is reduced too. For example, if you have a 500# spring you have to put a 1000 lbs on it to compress it 2 inches. Compared to this (assuming the actual wheel rate is the same, and they are fairly close if you check out where the rocker actuator rod attaches to the trailing arm) it would only take 666 lbs to compress the same 500# over 2", so to carry the same load you will need a 1.5* bigger spring rate. This is just a crude example, the reality is that as the rocker angles the relationship changes, for every Z of wheel travel the shock/spring don't move 1/ratio * Z because angularity comes into play on both the pushrod side and the shock side. Looking at the pics, on the pushrod side it looks to pretty much stay close to ideal but on the shock side with the ratio in play there the shock compression vs. suspension compression gets uglier than it is in the 90 deg. angle to the cam you see in the pic. So in reality, if you take the example above, it takes relativly less and less additional spring load to compress the suspension. So, unlike the simple explanation above where the actual effective rate stays the same, in reality it does not because of the angular effects This means that the softest spring that you can use to keep the suspension from hitting the bump stops will be a higher rate than if you had a 1:1 ratio. A ratio promoting increased shock & spring travel for a given suspension travel is favorable because it increases the efficiency.
Check out this photo:

Notice how the pushrod is much closer to the pivot than the shock, this is because this race car has very limited suspension travel and this allows them to still use the full (or close to) stroke of the shock and the complete range of the spring load through it's compression.
Another thing, sure coil overs allow you to adjust ride height, however static ride height should be set by design first and foremost. You determine the expected suspension travel (and add a little) and then check what your bump and rebound positions will be for the unsprung mounting point, and then you select a shock to suit the extended and compressed lengths (so that the spring doesn't sit loose in the coil over because you have a too long extended length shock so that you have tu run the collar all the way down and run the spring on the last bit of travel it has before hitting full compression), or you choose the lower mounting point to suit the closest fitting shock you can find. This way you can use the adjuster collar to preload the spring and thus affect the stiffness(see if you adjust the collar to preload the spring by 1" compression the spring load starts off there and climbs by the rate from there on) This way you can select the spring you want to suit your suspension and vehicle dynamics, instead of having to select a certain minimum rate because otherwise the ride height is too high (collar won't adjust lower) or the other way around. It also allows you to for example set your suspension firm but not gaining such a spring load (by rate) through compression that it appears rock hard. For example, my rear coil overs use only 450lbs springs and the shocks are in front of the spindle, giving it a lever ratio in regard to the wheel such that they would normally act as a maybe 300 lbs rear spring. Now adjust the collar 1" and it takes 900# on the spring to compress it another inch. Does this act the same as if I had used a 900# spring with the collar just tightened? No, because @ 2" compression the spring load will be only 1350 lbs compared to a whopping 1800 for the 900 pounder.
Just noticed another thing, with the suspension static your shock is perpendicular to the rocker, it would have been better to move the shock mounting point on the rocker outboard (relative to the pivot point), that way when the rocker tips it goes towards a perpendicular state and then away from it again. This means that over the entire susp. travel the rocker moves around the ideal situation with max effective shock engagement (the angles are kept close to perpendicular, reducing the angular loss of efficiency), your system is most effective in this static condition and gets worse once the suspension bumps.
Last edited by V-Twin; Mar 14, 2008 at 08:50 AM.
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Last edited by Solid LT1; Jul 10, 2009 at 12:49 PM.





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