electric radiator fan question
I guess technicians don't learn the simple thinks like Kirchhoff current law anymore - the sum of currents flowing into a node is equal to the sum of currents flowing out of that node. Node = gauge in this case.
The alternator charges by making the voltage at the alternator higher than the voltage at the battery. With the voltage at the alternator higher than the battery, the current flows towards the battery. Changing the gauge of wire won't make the alternator voltage lower than the battery voltage or cause the current to reverse directions.
Showing the same as before means nothing when you changed where the fan gets it's power. That change completely changes what the gauge should show. Since the pump and fan are powered from the battery, the ammeter should show the alternator current that is running the fan and pump and plus the current that is charging the battery. It should NOT just show the current that is charging or discharging the battery. But whatever, it's already obvious that you're ignoring the fact that your new pump and fan wiring means that a true 1-2A on the ammeter with the fan running means the battery is being discharged by about 15A. Probably due to more bad advice from the technician on this too....
Last edited by lionelhutz; May 16, 2018 at 04:16 PM.










