Cam and Rocker math?
Thread Starter
Le Mans Master
Joined: Aug 2000
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From: Semper ubi, sub ubi
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Cam and Rocker math?
If you have a cam with an advertised intake lift of 0.474 and exhaust lift of 0.510, I assume this would be with 1.5 rockers. What would the effective lift of the cam be with 1.6 rockers? Would it be 0.474 * 1.1 = 0.521? For some reason this doesn't look right to me. Or would it be .0474 * 1.067 = .506? Or is it neither of these formulas?
I was given these by 2 different sources, and I'm not sure either of them are right.
I was given these by 2 different sources, and I'm not sure either of them are right.
Drifting
Joined: Mar 2001
Posts: 1,514
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Re: Cam and Rocker math? (Smokehouse69)
The most accurate would be the cam lobe lift * 1.6 ratio of the rockers. You can work backwards .474/1.5 = .316 and .510/ 1.5= .340, so you get
intake .316 * 1.6 = .5056 and exhaust .340 * 1.6 = .544. I think thats the way to do it. I'm sure I'll get corrected if wrong :lol:
Scott
intake .316 * 1.6 = .5056 and exhaust .340 * 1.6 = .544. I think thats the way to do it. I'm sure I'll get corrected if wrong :lol:
Scott
Thread Starter
Le Mans Master
Joined: Aug 2000
Posts: 9,662
Likes: 7
From: Semper ubi, sub ubi
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Re: Cam and Rocker math? (Fevre)
Thanks guys, it looks like the LIFT * 1.06666 gives the same results as LIFT/1.5 * 1.6
The formula I was given was actually 1.6/1.5=1.06666 * LIFT which is basically the same.
The formula I was given was actually 1.6/1.5=1.06666 * LIFT which is basically the same.
