engineers and math geeks - vibrational cause?
Since putting in a fidanza flywheel and new clutch into my car (86 - with ZZ4 motor and Tremek tko500) I have a vibration that appears at 3200 RPM and gets progressively worse - first time it happened I though someone had sold me flat spotted racing slicks.
Since it is RPM specific - the first thought was flywheel - but no such luck. I think that I have found the answer - but vI don't wan't to put it all back together and find out I missed.
The pressure plate turns out to need 20 grams (about 2/3 of an ounce - think 2 quarters) to balance. That seems to me to be plenty to cause the vibration - but I just wanted an edumacated verification or denial - would 20 grams lead to a noticeable vibration at 3500 RPM?
Carl Johansson
RACE ON!!!
Since putting in a fidanza flywheel and new clutch into my car (86 - with ZZ4 motor and Tremek tko500) I have a vibration that appears at 3200 RPM and gets progressively worse - first time it happened I though someone had sold me flat spotted racing slicks.
Since it is RPM specific - the first thought was flywheel - but no such luck. I think that I have found the answer - but vI don't wan't to put it all back together and find out I missed.
The pressure plate turns out to need 20 grams (about 2/3 of an ounce - think 2 quarters) to balance. That seems to me to be plenty to cause the vibration - but I just wanted an edumacated verification or denial - would 20 grams lead to a noticeable vibration at 3500 RPM?
Carl Johansson
Really depends on where the extra weight sits.
heres a formula for you..
F=ma
Fbalance= mass(of imbalance)x accleration normal to the weights velocity
F due to imbalance = mass x v^2/r
F due to imbalance = mass x (omega*r)^2/r
F due to imbalance = mass x (omega*r)^2/r
v=omega*r so really
F due to imbalance = mass x r omega^2
omega * (2pi Rev per sec/ radians per second) * 60 RPM/ Rev per sec
F due to imbalance = mass x r*RPM*2pi*60
so if you got 20 grams located about 6 inches from from center at 3200 RPM you basically have
.020*.15*3200*2*pi*60= 3617.28newtons
which is around 800 lb-force at any instant.
They are probally balanced quite a bit closer to the flywheels center than that.
Carl Johansson
yes
The Best of Corvette for Corvette Enthusiasts
- think 2 quarters) to balance.
I gather it has seen service now with you but was it new before you
used it? I would normally expect that the PP would be neutral or
close to it.
.
heres a formula for you..
F=ma
Fbalance= mass(of imbalance)x accleration normal to the weights velocity
F due to imbalance = mass x v^2/r
F due to imbalance = mass x (omega*r)^2/r
F due to imbalance = mass x (omega*r)^2/r
v=omega*r so really
F due to imbalance = mass x r omega^2
omega * (2pi Rev per sec/ radians per second) * 60 RPM/ Rev per sec
F due to imbalance = mass x r*RPM*2pi*60
so if you got 20 grams located about 6 inches from from center at 3200 RPM you basically have
.020*.15*3200*2*pi*60= 3617.28newtons
which is around 800 lb-force at any instant.
They are probally balanced quite a bit closer to the flywheels center than that.
Yeah, Jimmy Neutron!
I gather it has seen service now with you but was it new before you
used it? I would normally expect that the PP would be neutral or
close to it.
.
Thats why both Carolina and Fidanza recomend spinning the flywheel and PP together before you install em - slight flub up by my mechanic - he assumed I was getting him good parts!
Carl Johansson
Last edited by Carl Johansson; Dec 7, 2005 at 09:38 AM. Reason: add more info
What?? Its just f=ma..
you can write a book on the differnt things you can solve with F=ma.. one of my favorite things is showing how the weight of a car means absoulutely nothing on how much g's you can pull with it nor does it mean anything on when it will tip over.













