I think I have my math right here, and i know its not perfect because a car doesnt accelerate uniformly from Zero to 60mph as it does from A stop to 60', but with that assumption this is how it goes.

Xf=A*Td
Td=1.5
Xf=60

Vfmph=88
Vfmph=1/2*A*Tmph^2

The variables arent too hard to figure out, the first EQ is determining the acceleration from a 60" time and the second is determining a time that with that same acceleration it would take a car to reach 60MPH or 88fps.

if you notice any errors let me know or have a better idea how to convert.

I used 1.5s for a 60' time because that is my best, here are a few more, if you want a specific time let me know ill calculate it for you.

1.0=1.713
1.2=1.876
1.4=2.026
1.5=2.098
1.8=2.298
2.0=2.422

Discuss

 

so you are saying if you pull a 2.0 60' that you are going 0-60 in 2.4 seconds... that is way off.

 

 

Your 0-60mph are way to quick for the times

 

Drive many cars of varying performance capabilities (i.e., from C6 Z06 to an older slow 4-cyl. or diesel car) at the track. More data points the better, especially across a wider performance spectrum.

Take note ***only*** of the 60 foot times whose corresponding 1/4 mile times/mph matching magazine times. In other words if you have a 1/4 mile timeslip of 12.6 s @ 114 mph for a C6 6-speed, then jot down the 60 foot time YOU GOT since one of the mag. got a 1/4 mile time like that and it's admissable data. Also jot down the magazine's 0-60mph time. There's your first data pair: your 60' time and the magazine 0-60mph time. Repeat for vehicles of widely varying performance capabilities.

Then do a polynomial fit (2nd order would be the minimum) through those points since every 0.1s reduction in 60' times results in a non-linearly decreasing 0-60 mph time.

MATLAB has a function called polyfit and some graphing programs can do fits too. The goal is to get y = fcn(x) where the function is at least 2nd order or higher, x = 60 foot time as a function input, and y = the 0-60 mph estimate as your output.

At the end you'll have an empirically based formula (which is the best since empirical is reality-based) for correlating 0-60 mph times and 60 foot times. I guarantee this is the best route to getting a good formula.

 

Ranger, with the C6Z, is getting 1.68 / 60 ft times, with 3.0-3.2 seconds for 0-60 MPH.

And this is in a vette that hits 60 in first gear.

 

I found this somewhere a long time ago. It seems pretty accurate.

60' to 0-60 conversion
--------------------------------------------------------------------------------
2.3 second 60' time = 35.5 mph @60' = 7.0 second 0-60 time
2.2 second 60' time = 37.1 mph @60' = 6.5 second 0-60 time
2.1 second 60' time = 38.9 mph @60' = 5.9 second 0-60 time
2.0 second 60' time = 40.9 mph @60' = 5.2 second 0-60 time
1.9 second 60' time = 43.0 mph @60' = 4.6 second 0-60 time
1.8 second 60' time = 45.5 mph @60' = 4.0 second 0-60 time
1.7 second 60' time = 48.1 mph @60' = 3.4 second 0-60 time
1.6 second 60' time = 51.1 mph @60' = 2.9 second 0-60 time
1.5 second 60' time = 54.5 mph @60' = 2.2 second 0-60 time
1.4 second 60' time = 58.4 mph @60' = 1.5 second 0-60 time
1.36 second 60' time = 60.0 mph @60' = 1.36 second 0-60 time
1.3 second 60' time = 62.9 mph @60' = 1.2 second 0-60 time
1.2 second 60' time = 68.1 mph @60' = 1.1 second 0-60 time
1.1 second 60' time = 74.3 mph @60' = 0.9 second 0-60 time
1.0 second 60' time = 81.8 mph @60' = 0.7 second 0-60 time

 

I agree with that chart. I did a polynomial fit on some of my drag runs last year and a 1.8 60' is about a 4.1 sec 0-60.

 

Cool, I got the conversions i was looking for, that table takes care of it, thanks!