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to get crank HP, take RWHP and divide by .85 (manauls) or .83 (autos)
so drivetrain loss is greater in manuals?
400rwhp/.85=470fwhp vs. an auto which would be 400rwhp/.83=482fwhp
therefore all stock A4's have a hp advantage over M6's???
I guess you could say that a stock car has the hp rated @ the flywheel so the equation works to show A4's have less rwhp but in the real world we don't get data from flywheel dyno's...just rw dyno's.
so when I dyno next to an A4 and come out with identical #'s then the A4 has more fwhp???
to get crank HP, take RWHP and divide by .85 (manauls) or .83 (autos)
so drivetrain loss is greater in manuals?
I guess you could say that a stock car has the hp rated @ the flywheel so the equation works to show A4's have less rwhp but in the real world we don't get data from flywheel dyno's...just rw dyno's.
so when I dyno next to an A4 and come out with identical #'s then the A4 has more fwhp???
400rwhp/.85=470fwhp vs. an auto which would be 400rwhp/.83=482fwhp
therefore all stock A4's have a hp advantage over M6's???
[Modified by Gary2KC5, 12:53 PM 6/1/2002]
a 470 hp motor in a manual = 400 at the rear wheels (400 rwhp/.85 = 470 hp)
a 470 hp motor in an automatic = 390 @ the rear wheels (390 rwhp/.83 = 470 hp)
The manual is more efficient at transferring power to the rear wheels. :smash:
to get crank HP, take RWHP and divide by .85 (manauls) or .83 (autos)
so drivetrain loss is greater in manuals?
400rwhp/.85=470fwhp vs. an auto which would be 400rwhp/.83=482fwhp
therefore all stock A4's have a hp advantage over M6's???
I guess you could say that a stock car has the hp rated @ the flywheel so the equation works to show A4's have less rwhp but in the real world we don't get data from flywheel dyno's...just rw dyno's.
so when I dyno next to an A4 and come out with identical #'s then the A4 has more fwhp???
[Modified by Gary2KC5, 12:53 PM 6/1/2002]
No, I think your misunderstanding. Your using an example that starts with 400RWHP for both cars. Thus since and A4 has more parasitic loss than a manual, you have to have MORE HP for an A4 at the crank, to achieve the 400RWHP figure relative to an MN6. Your example in fact proves the MN6 is more efficient.
...Your using an example that starts with 400RWHP for both cars...
I can see how the equation works when you know the FWHP and want to calc the RWHP.
My misunderstanding is when you only know RWHP, like on a dyno.
On my last dyno run it resulted in 355 rwhp. I noticed that WallstAl's sig also shows dyno #'s of 355 but he has an A4. therefore what your saying is that the A4 has more FWHP to generate the same RWHP?
...Your using an example that starts with 400RWHP for both cars...
I can see how the equation works when you know the FWHP and want to calc the RWHP.
My misunderstanding is when you only know RWHP, like on a dyno.
On my last dyno run it resulted in 355 rwhp. I noticed that WallstAl's sig also shows dyno #'s of 355 but he has an A4. therefore what your saying is that the A4 has more FWHP to generate the same RWHP?
Correct. An A4 needs more FWHP, to achieve an equal amount of RWHP compared to an MN6.
When calculating FWHP Loss, you subtract a percentage from the crank.
An A4 looses more than a MN6 by the time it reaches the rear wheels.
When calculating RWHP, you take the inverse proportion. To simply add (for instance in an MN6 355rwhp * 1.15) would be wrong. You must take 355rwhp / .85