Negative Horsepower
I will try to post the plot, I am not yet sure how this works:
http://www.corvetteforum.de/attachme...entid=722&sid=
The grey line you see at the bottom is called "Schleppleistung" in German. It shows the drivetrain loss vs rpm. I think you start at max rpm and take your foot off the accelerator. At max rpm, energy is stored in the rotation of the dyno. This rotational energy of the dyno is consumed by the friction in your drivetrain (negative power), resulting in dropping rpms. So you get the power consumed by friction vs rpm.
Of course there is some calibration involved, since the dyno also has internal friction.
I am not sure if you press the clutch during this procedure, and calculate corresponding engine rpm from the rpm of the dyno. I will call the tuner on monday and ask.
Anyway, for my car I got a drivetrainloss of 17% in fourth gear and with a 3.73 diff.
Till
[Modified by till, 9:36 AM 3/8/2003]
Anyway, I'm not sure what to make of the graph, as it shows I was only losing 35rwhp at 140mph. Maybe you are supposed to take the number the dyno jet gives you and then add a static number to the graph as well to get total loss, since there's no load on the drivetrain and thus, probably less friction. I could take a pic of the graph and post it, its strange looking, and its definitly on a curve, not a linear thing (increasingly lossy as mph goes up).


vetterdstr :cheers:


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Example: take a standard transmission/driveshaft/axle combo hooked up to a 100hp engine. Current "% of HP" calculations would tell you that 15hp of this engine's output is being taken up via "drivetrain loss".
Now swap that 100hp engine for a 1000hp engine. "% of HP" calculations tell you that the exact same drivetrain that used up 15hp in the first test is now using up 150hp. Why are drivetrain losses significantly changed just because the engine has changed? Doesn't make sense, does it?
I would think that drivetrain loss would be on a scale totally independent of, and unaffected by, engine HP. It would be a sliding scale starting at zero HP (at zero drivetrain RPM), and be a fixed number for any given point on the drivetrain RPM scale.
I'm surprised no one has done this already -- seems like a simple test to conduct. Get a C5, pull the engine, and attach an electric motor/measuring device to the tranny input shaft:
* How much HP to drive a C5 manual trans drivetrain at 1k RPM? At 3k RPM? At 6k RPM?
* How much HP to drive a C5 auto trans drivetrain at 1k RPM? At 3k RPM? At 6k RPM?
[Modified by Kent1999, 3:47 PM 3/9/2003]
Sir Isaac Newton did a really good job in trying to explain this mess with his amazing insights into the laws of motion and the conservation of energy. Not sure he'd have driven a 'vette though what with him being a Brit ;)


* How much HP to drive a C5 manual trans drivetrain at 1k RPM? At 3k RPM? At 6k RPM?
* How much HP to drive a C5 auto trans drivetrain at 1k RPM? At 3k RPM? At 6k RPM?
A car also has fluid in the drivetrain. Drag due to motion through a fluid increases with the square of the velocity. The coefficient of friction for these fluids is very low (in the case of bearings, etc.), so the velocity has to get quite high before there is a significant effect. The transmission and rear-end have gears moving through fluids; here the drag is higher, especially in areas where the teeth are perpendicular to flow.
The old 15% rule probably isn't a bad ballpark guess given the constant and dynamic friction in a car's drivetrain.
Knowing the frictional losses allows them to determin the enegry captured by the piston and transfered to the crankshaft. Knowing the geometry of this system, they can compare the expected energy with the measured energy. THis tells them about the efficiency of the ignition and burn rate ot the 'gasoline'.
In principle, one could do the same by removeing one spark plug/wire. The difference IS the power produced by that cylinder.
*They have to mis-fire cylinders in a special way to avoid things like crankshaft failures,...

















