tire math ?
3.7in 13.2in 26.4in 83.0in
4.0in 13.0in 26.0in 81.8in
my question is diameter total highet of wheel
and circumfrence is the same as if i took a piece of string and brought it around the outside that would be my circumference
and diameter is width of tire (footprint)
is this all correct
3.7in 13.2in 26.4in 83.0in
4.0in 13.0in 26.0in 81.8in
my question is diameter total highet of wheel
and circumfrence is the same as if i took a piece of string and brought it around the outside that would be my circumference
and diameter is width of tire (footprint)
is this all correct
Last edited by dennis50nj; Feb 14, 2007 at 03:07 PM.
3.7in 13.2in 26.4in 83.0in
4.0in 13.0in 26.0in 81.8in
my question is diameter total highet of wheel
and circumfrence is the same as if i took a piece of string and brought it around the outside that would be my circumference
and diameter is width of tire (footprint)
is this all correct
2) and circumfrence is the same as if i took a piece of string and brought it around the outside that would be my circumference -- yes, circumference or how far your tire travels in one rotation.
3) and diameter is width of tire (footprint) -- no, see #1.
Say you have a 245/35/18 tire --
245 is the width in millimeters (mm).
35 is the aspect ratio -- meaning what percent of the width is the sidewall height -- in this case 35%.
18 is the tire (and wheel) diameter.
To find the width of the tire in inches divide 245 by 25.4 (the number of mm to an inch) -- 245 / 25.4 = 9.65 inch.
The sidewall height is 9.65 inch times .35 (35%) -- 9.65 * 0.35 = 3.38 inch.
The diameter of the tire (and total height of your wheel) is 3.38 inch times 2 (you have to count top and bottom sides of the tire) plus the rim diameter -- 3.38 * 2 + 18 = 24.75 in.
Circumference is diameter times pi or in this case -- 24.75 * 3.1416 = 77.75 inches.
--Dan
2) and circumfrence is the same as if i took a piece of string and brought it around the outside that would be my circumference -- yes, circumference or how far your tire travels in one rotation.
3) and diameter is width of tire (footprint) -- no, see #1.
Say you have a 245/35/18 tire --
245 is the width in millimeters (mm).
35 is the aspect ratio -- meaning what percent of the width is the sidewall height -- in this case 35%.
18 is the tire (and wheel) diameter.
To find the width of the tire in inches divide 245 by 25.4 (the number of mm to an inch) -- 245 / 25.4 = 9.65 inch.
The sidewall height is 9.65 inch times .35 (35%) -- 9.65 * 0.35 = 3.38 inch.
The diameter of the tire (and total height of your wheel) is 3.38 inch times 2 (you have to count top and bottom sides of the tire) plus the rim diameter -- 3.38 * 2 + 18 = 24.75 in.
Circumference is diameter times pi or in this case -- 24.75 * 3.1416 = 77.75 inches.
--Dan
The calculator isn't perfect. For example, it shows the stock C6 Z06 size as "unknown." If it shows that a wheel is too wide or narrow for a given size, you can trust it though.
GL!
make one revolution put the second tape down and mark it.... (at the first mark from tire)
measure the distance of the two tape marks and divide that by 3.14 and it will give you a "loaded" diameter (what the car actually sees)....
the numbers will be different if say the tire was close to flat... (smaller diameter) or over-filled (larger diameter)...
as far as "footprint" goes - (part that touches the ground)... a tire will have a larger foot print if it flat...
and of course the opposite is true if over inflated.... (same size tire)
sorry.... very general - quick explanation.....
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