Package question...?





Question, what is your package if you break out?
Example> 12.0 dial, ET 11.95, .100 light???????
Thanks for the explanation......







How can you win with the worse package.... duhhhhhhThat makes NO sense.. the best package will always win.. unless of a breakout or other infraction!
You lost yesterday because your opponent had a .0009 BETTER package !! Think about it...
Like Fuzzy said if there is a breakout package dont matter... or if someone crosses the center line.. BUT if neither car breaks out, & there is NO red light the best package will always win..


How can you win with the worse package.... duhhhhhhThat makes NO sense.. the best package will always win...
Have agreat package and still lose it means nothing.
that "racer's math" didn't work...
When he was awarded the NHRA Division 1 Track Operator of the Year Award that season, I just
[Modified by Glensgages, 10:27 PM 5/30/2004]
The Best of Corvette for Corvette Enthusiasts





Racer A cuts a very poor light, 2/10 slower than his opponent, & runs 2/10 over his dial.
Racer B with the 2/10 better RT runs .08 faster than his dial in number..
Can racer A get to the finish line 5/10 ahead of racer B????
Is that possible?
Racer A cuts a very poor light, 2/10 slower than his opponent, & runs 2/10 over his dial.
Racer B with the 2/10 better RT runs .08 faster than his dial in number..
Can racer A get to the finish line 5/10 ahead of racer B????
Is that possible?
I'll try to make it as simple as possible...
Both Racer 'A' and Racer 'B' have dial-ins of 14.00
Racer 'A' cuts a .700 light (on the 'older' .500 system), and runs 14.200 on his 14-flat dial;
Racer 'A' has a 'package' of .400 (.200 on the tree, and .200 on his run)
Racer 'B' cuts a perfect .500 light (2/10s better than Racer 'A'), but runs 13.920 (.080 faster than his dial) on his 14-flat dial-in.
While Racer 'B' has a better 'package', the 'break-out' (running quicker than his dial) over-rules this fact, just as would a foul-start.
Racer 'B' would hit the stripe .480 seconds ahead of Racer 'A':
Racer 'A' had a .400 package, and Racer 'B' broke-out by another .08 (.400 = .080 = .480)
{Think of running-under as hitting a baseball 700', but into foul territory...impressive, but not worth a damn...}
I believe the above 'theoretical' ET slip would show a Morgin-of-Victory of .280 seconds:
.200 that Racer 'A' was "to-the-good", and .08 that Racer 'B' run under...
Does that help?
Racer B with the 2/10 better RT runs .08 faster than his dial in number..
Can racer A get to the finish line 5/10 ahead of racer B????
Racer A has a .400 disadvantage. A .200 slower light plus the .200 over his dial. Racer B gets to the finish line .408 ahead of racer A. Racer A wins, because racer B broke out. The B lane crossing first by .408 comes from the .200 better tree, plus the deficency in A's ET/dial of .200 plus the .080, under his dial, break out. It's all simple arithmetic.
RACE ON!!!
[EDIT] Speaking of "simple arithmetic", I AM aware that .400 + .080, does NOT equal .408. Opps!
[Modified by CFI-EFI, 9:49 AM 5/31/2004]





The faster dialed car's tree must have went off later than the dial in differential in my example.
Both racers numbers on the slip would appear to be correct,> based on when they broke the starting beam, but only a delayed tree could account for racer A getting to the stripe 1st & the large MOV..
Thanks...
but if you 'leave' on your opponent, and run-under/further-under than your opponent...
Ain't no-how he's taking the stripe first, unless there is an equipment/timing system glitch (i.e.: wrong haed-start, electrical problem, etc.).






