The half shafts





Yes they hold up the whole car. Frame, body, seats and all!
And why is someone else taking your car apart?





Not until the suspension was reassembled would I set it down. The fact that you seen your car off the stands with I don't know, the tires on the inside of the fenders holding it up? The trailing arm on the bump stop perhaps? Lets hope so.
Unbelievable. This is why you work on your own car. No one loves your car as much as you do!
That said, the halfshafts, like the upper control arms in front, are an integral part of the suspension geometry so when removed, will allow the rear wheel camber to change, putting undue stress on the trailing arm bushings but not to the degree you mention.
Bottom line, the car should be supported on the frame while the halfshafts are removed.





As you know, the differential is hard mounted to the frame via a crossmember and the transverse spring is hard mounted to the differential. That force travels to the ends of the spring, then up the bolts attached to the trailing arm. From there, it goes to the bearing carrier, axle, wheel and, finally, the tire.
The halfshaft is not in that pathway. Yes, it is a 3-point IRS but the halfshaft only serves to locate the upper point of the trailing arm in the vertical plane. Removing a halfshaft has no effect on that force path (because it is in the unsprung weight category).
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So he must have some blocks of wood in there holding it up. He probably needs his lift for other projects and blocked it so he could roll it. It's not being driven, so it should be fine. When he puts it all back together it'll be fine. Relax. I didn't know your diff. was out .
The Chevy way of measuring the rear ride height is the rear strut rods. The difference between the inner joint and the outer joint is called the "D" height.
Spec there is 2.1" with zero passengers.
I next removed the left halfshaft.
Remeasured the distance between the same points - exactly as before - 29 7/8”.
Left side with halfshaft installed
Right side with halfshaft installed
Left side with halfshaft removed
Scene of the experiment





What you didn’t address is the lack of any change in the vertical plane which is precisely my point - the halfshafts do not bear any weight. While it is true that removing them on a fully assembled car, particularly with old trailing arm bushings, will cause the wheels to “tip” inward at the top (and thus a perceived loss of ride height), there is no actual change to the ride height.





like I said. Put a car on that. Put it down on the ground and get back to us.
Or, just look at the damage caused when a half shaft is no longer connected to a moving car.
Or explain to us why our diff yokes wear when there is no weight or pressure on them.
like I said. Put a car on that. Put it down on the ground and get back to us.
Or, just look at the damage caused when a half shaft is no longer connected to a moving car.
Or explain to us why our diff yokes wear when there is no weight or pressure on them.
Last edited by augiedoggy; Jun 13, 2024 at 10:08 AM.
Here is my poor drawing:
Here is the best I can simplify the physics:
720 lb force car weight downward on 1 spring bolt (red)
equal resisting force upward in center of tire (red)
tire, axle & trailing arm resist 720# vertical force
but ~7 inches between points (blue)
the trailing arm bushing is the pivot point
720# force trying to rotate the trailing arm with a 7” lever arm
This is a 420ft-lbs rotational torque on the trailing arm from tire axle
top of tire tips in with 420# force with 12” lever arm (yellow)
the halfshaft is attached to the trailing arm pivot point
no sideways force at the halfshaft (small green) it is just a locator
rotational torque has to be resisted by something, half-shaft is at the pivot point, so it can’t, so it is up to the lower strut rod
lower strut rod (long small yellow) 840# force, only 6” lever, resisting tire rotation, due to car weight
Take the half shaft out as 69L88 did, and not much would happen.
Take the strut rod out, and the tire crashes into the upper frame with 420# force
Add a G cornering force of 500# at bottom of tire tread (green)
500# of horizontal force is resisted by both half shaft and lower strut rod, say 250# each
But also a 500 ft-lbs of rotational force on tire at the trailing arm, due to 12” lever
This is resisted almost entirely by the lower strut rod, 1000# of force, 6” lever
If cornering uses strut rod as a pivot point, half shaft tries to pull out of diff with 500# of force on one side of car, and is crushed into diff with 500# force on the other side of car. That causes diff pin wear, when the posi rotates under all that pressure.
(Wish I could find that video where the axle stub pops out of the guys diff in a corner)
Is it any wonder why the lower strut rod bushings and diff cross pins take such a beating?
They can get hit with up to 1000# of force, cycling on & off very quickly.
And the axles get rotated on the cross pins while under all that pressure.
Ok As I finished that I thought of an even easier way.
Think of the tire trying to rotate the trailing arm as a torque wrench.
It is 7" long. And set at 420 ft-lbs
As you push up at blue arrow, the car weight, spring, thru the spring bolt, push down at the red arrow.
I know all of you know how a torque wrench works.
If the spring is strong enough at red, the TQ wrench does not move vertically, but the handle rotates at blue.
There is virtually zero pressure right to left.
Or in this case, along the half-shaft.
Thanks for the mental exercise.
I needed it, and that one made me work!
Vette IRS is unique!
Last edited by leigh1322; Jun 15, 2024 at 01:19 AM.





You are both correct and wrong it's just the point you are stuck on and at what point in a dynamic suspension travel you are at
Now quit arguing so I can go enjoy some sunshine at a Cops and cars event to support Veterans and first responders










