Drag racing question
You launched your car in 4th gear and just left it there through the entire run? What would your MPH be at the end of the track? Would it be the same as your MPH if you raced normally?
Thoughts?
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This is an easy one. For constant acceleration travel, from a standing start, Vf^2=2*a*x
where x=1/4 mi (distance traveled), a=the constant acceleration level
If you are in 4th gear you will not be able to use the leverage of the lower gears to accelerate your car nearly as fast. So your Vf will be wwway low compared to normal.
Vf is a perfect indication of A. A depends on your vehicle weight, the gears, and the motor.





The track is a fixed length.
Your motor doesn't make constant power across the powerband, and that's why the mph will be lower. Because your rate of acceleration will be lower in the rpms below the powerband.
I don't think the 1:1 final drive ratio will allow the engine to accelerate the car at nearly the same rate over the 1320 foot distance, resulting in a much lower MPH at the end of the track.As someone mentioned earlier, a heavier car would be affected more.
But what do I know - my car hasn't been doing ANY accelerating lately. I just enjoy seeing Nathan and Jesse agree!
In the middle of last summer he installed 4:10s. With everything else the same, he ran a bunch of 11.9x's at only 112-114.
He then brought the car to a shop for some tuning and another pulley change. The baseline dyno test before the new pulley and the tune indicated a drop in rwhp to about 430 and a drop in rwtq to about 450 just with the gear swap. After the new pulley and tune, the rwhp was about 450 and rwtq was about 480. The car ran a 11.70 at 116 after this.




