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I just went out and disconnected my CTS harness and tried to ohm the CTS. It looks like the FSM says at 70*f, it should read about 3,400 ohms. My harness reads 4.85v. It should work right??
I know Bogus, I even double checked and yes it was set on ohms. I tried to ohm the signal side with red lead and a known grond on the frame with black lead. Then I tried to ohm the signal side with red lead and black lead on the ground side of CTS. When I turn the meter to volts the harness reads 4.85v, but got 0 for ohms on the CTS. I guess this is a yes/no type of question with a little insight for more than I know.
If your set on ohms, and you get 0L, you've got an open circuit at any temp! At normal operating temps (85 to 95C) the voltage should measure 1.5-2 volts. Read both codes 14 and 15.
You can ohm out the CTS and you did that correctly it sounds fine. But you can’t ohm out the harness which is really looking back into the PCM (ECM) electronics. The PCM puts out a 5 volt reference signal which you measured. The PCM uses this voltage to interpret the resistance of the CTS and use it for its calculations.
It is not a good thing to measure resistance back into the harness because the meter on ohms does put out a voltage and you are sending that back into the PCM. Not a good thing to do, you could damage the sensing circuitry.
I would say that it would work right because the resistance of the CTS is OK. You can’t tell anything by measuring the harness voltage other than it is there which sounds OK.
You have to know what a voltage should be for it to be useful data. Other sensors can be measured for useful information (i.e.; MAP & TPS), but not much gain with the CTS.
I don't see where you measured the resistance of the sensor itself. Set meter to ohms and connect leads to each terminal of the sensor itself with harness disconnected. In that case you should get a reading of ohms that correlates to a temperature such as 3400ohms at 70*.
Correct me if I'm wrong, but it seems you tested the harness and output from the PCM but you do not mention actually getting any ohm readings from (across) the sensor itself.
excuse me, just so I know, how can you get 0 ohms on an ohms test that should read anywhere from 185 ohms all the way up to 100,700 ohms depending on temperature...that's according to the FSM.
6E3-A-27, or 6E3-A-29. I'm lost here, and if his ohm meter was actually reading 0L, he has a problem with an open circuit! Help me here?
I disconnected the CTS from the connector and did a voltage check of the yellow and black circuit wires. The yellow measured 4.85/ close enough to the 5 the ECM sends with the key on and code key in place. I then turned to ohms and stuck the red lead into the CTS and the ohm meter read 0 even after wiggling the lead around. I had the black lead on a known ground and then on the TPS ground which is the same ground for the CTS and MAT. I never saw an ohm reading with all of this. It was a little difficult sticking the red lead in there with it still on the intake manifold but did good enough I should have got a reading. I did it correctly. When using an ohm meter how do you guys check the ohm reading of the CTS while still in the manifold??
The leads should be touching the the sensor terminals. Not one to a terminal and the other to some other ground. Across the terminals as it it sometimes refered to. And it really doesn't matter which lead is on what side.
I'm going to assume your working on your 95. With your ECT unplugged If you measure from ground to either lead of the ECT it should not measure any ohms or infinity (not 0). There should not be any connection to ground from any terminal of the sensor. The reading is measured across the two terminals of the ECT.
I have to use terminal extenders to make the measurement myself. They are to recessed and I can't see them. If you are really measuring the sensor on the water pump and the reading is 0 ohms to ground, then the sensor could be shorted to ground. If you are measuring correctly.
I would get a known value resistor say 1000 ohms and measure it just to make sure the meter is working OK.
The leads should be touching the the sensor terminals. Not one to a terminal and the other to some other ground. Across the terminals as it it sometimes refered to. And it really doesn't matter which lead is on what side.
Again, meter leads to sensor terminals.
I was measuring resistance on my 86 CTS. I tried to measure the sensor itself with the red and black leads both inside the sensor. My meter said (I) and never moved even after trying to touch both inside terminals. If this is correct and I did not get a reading, then this means my sensor is faulty. I do not have a code 14 or 15. Could the sensor be bad and still not show a code 14 or 15? I guess anything is possible. Thanks guys
Just some suggestions;
1) Make sure the meter is working right.
2) Make sure you are on a scale that will allow you to measure the resistance value you expect to see (if you don't have auto ranging).
3) Are you sure you are making contact with both terminals of the CTS.
If all is good then you might have a bad (open) CTS.
Just some suggestions;
1) Make sure the meter is working right.
2) Make sure you are on a scale that will allow you to measure the resistance value you expect to see (if you don't have auto ranging).
3) Are you sure you are making contact with both terminals of the CTS.
If all is good then you might have a bad (open) CTS.
1) yes the meter is working I tested a old injector with it.
2) I tried it in 20, 200, 2,000
3) I wiggled both leads around in there for about 30 sec
Sounds like a bad sensor if this is the case.
I will give it one more try this afternoon.
Alright, I removed some of the crap in front of the sensor and used the ohm meter again. It reads 2,200 ohms and the ouside temp here is about 80-85*. I think it should read higher than that what do you guys think?
Sorry guys, It is reading correctly. At 70*f it should read 3,400 ohms and at 100*f it should read 1,800 ohms. It is about 85 here and it reads 2,000 ohms, just right. Well troublshooting paid off this time guess I'll save that $12. Thanks for everybody help on this one. Looks like case closed.