frying CAGS bypass units


If those 1064, 1016 and 1096 codes are in the RFA section of your DIC, then you can just disregard them.
HTH
Current flow is the result of voltage and resistance in the circuit (i=v/r). Since Voltage should be constant, and resistance is constant, the current should be constant. So either the voltage on that circuit is spiking or your resistor rating is low and burning out.
I can't recall if the voltage on that circuit is +5V and controlled by the BCM or not, so it's possible that the voltage is somehow higher than allowed but you'd expect other problems as well. Get a different CAGS unit and see if that works, and measure the impedance before installing just for your records. It may help if it happens again.


Current flow is the result of voltage and resistance in the circuit (i=v/r). Since Voltage should be constant, and resistance is constant, the current should be constant. So either the voltage on that circuit is spiking or your resistor rating is low and burning out.
I can't recall if the voltage on that circuit is +5V and controlled by the BCM or not, so it's possible that the voltage is somehow higher than allowed but you'd expect other problems as well. Get a different CAGS unit and see if that works, and measure the impedance before installing just for your records. It may help if it happens again.
katana ace: Let us know what happens if/when you get a chance to address this issue.





BC
The Best of Corvette for Corvette Enthusiasts





Nope!! The compoet inside the CAGS Module/Plug is a resistor. There are no polarity sensitive resistors. If the wattage is wrong and the current is high, it will just smoke.
You know what resistors are made out of,,right??? Smoke! Cause when you let the smoke out, they dont work any more.
BC


You know what resistors are made out of,,right??? Smoke! Cause when you let the smoke out, they dont work any more.
BC

A least that's what we called it in the Navy.





We smoked a radio receiver 24 VDC power supply just yesterday. Wow,, did it ever STINK! When we replaced the card, the Radioman said "SMOKE TEST" just before he flipped the breaker on!

BC
Last edited by Bill Curlee; May 8, 2007 at 06:30 PM.


Much akin to the smell of burning hair. Yacko!


Basically, as a rule of thumb, you can have a resistor that's too big with no ill effects; having one that is too small however usually causes it to burn out.
BTW, that solenoid presents an "inductive" load to the circuit when it "fires" and reacts differently than a "resistive" load and can have an affect on the proper design size of the resistor. Not trying to get too far into DC ciruit theory here.
Suffice to say: If the 1/2 watt works, fine. If not, a 1 watt would be next.





Basically, as a rule of thumb, you can have a resistor that's too big with no ill effects; having one that is too small however usually causes it to burn out.
BTW, that solenoid presents an "inductive" load to the circuit when it "fires" and reacts differently than a "resistive" load and can have an affect on the proper design size of the resistor. Not trying to get too far into DC ciruit theory here.
Suffice to say: If the 1/2 watt works, fine. If not, a 1 watt would be next.
E= I X R and P= I X E Formulas that I will always remember!
BC
I checked the one that I got and it was 15.1 ohms, so I checked the resistance across the solenoid and it was 13.6 ohms. I plan on putting in the one that I have and see how it does. I am however wondering where people are getting the 2.2kohm number?
If I were to assume a voltage of 14.5 which is what typical automotive components are designed to along with a 15.1 ohm resistor, then the current draw on this circuit would be 0.96 A and the resistor would need to be 13.9W (V=IR and P=IV). With a 2200 ohm resistor, the
current draw would be .00659A and the power drawn would be .095 W.
The schematic shown in the service manual doesn't show any other resistors so it would likely be possible to find the activation voltage by putting a multimeter across one of the tabs on the top side of a fuse and the other to chassis ground (hope that is clear).Hope the schematic below helps.
Now I am not an electrical engineer, but my friend is and he recommended that I use the 15 ohm resistor b/c by using the large resistor it would not clean the ignition relay properly and could result in reduced life, I plan on asking him a bit more about this tomorrow.
[IMG]
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Last edited by Autobot; May 11, 2007 at 02:45 AM.


From what I would guess, as long as the PCM doesn't see 12V then it assumes that the solenoid is working and doesn't send a code, but obviously you don't want too small of a resistance or you would end up burning up the insulation on the wires.






