I am looking to upgrade to this kit of 2 pc. rotor, and caliper brkt.

Not looking for Opinion, but knowledge as to how to calculate the increased braking force, due to more leverage, since the swept area remains the same

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Baer Front Rotor Upgrade Kit - 97-08 Corvette


http://www.pfyc.com/pc/VT4024/C6NEW/...+Corvette.html

Your Price: $599.99




The Baer Front Rotor Conversion Kit makes upgrading your front rotors to a larger size a breeze! The kit comes with a bracket to raise the caliper and converts 12.75" to 13.35" rotors. Kit works on standard wheel size for the C6, however larger front wheels are required for C5 conversion. This kit comes with two two-piece lightweight rotors and brackets. This upgrade gives you a C6 Z51 sized front rotor for your C5 or C6!

Application: 1997-2008 Corvette C5 and C6 (does not fit C6 Z06)

 

It looks like the kit only allows you to use a slightly larger rotor (0.60" more in diameter) and use a two-piece rotor. Same OEM caliper, number of pistons and brake lines. Are you achieving greater braking force? I think the primary benefit of the larger rotor is that it dissipates heat better than a smaller rotor. Personally, I would save your money and save up for the LG G-stop Wilwood 6-piston front rotors that work with your OEM rotors for increased braking force.

 

Some simple math would suggest a 4 % increase in the moment arm, increasing the surface speed by 4%, in simple words it will take a given force 4% less to do the same work as the smaller stock rotor. Of course you would never know the difference because the brake booster doesnt give real feedback. it will in effect create less thermal brakedown over the larger area.

 

This would be the better choice over all, but the two piece rotors are lighter even though they are larger.

 

good answer...

but no Math on the Leverage increase , it's part of the Equation ..
due to divorce, i lost all my good books ..

" Suspension Engineering " .. " Braking Systems Math " ..

and many more ..

do You remember Herb Adams ..??

 

It actually will provide more braking force due to the increased diameter even though the swept area stays the same. The bracket movers the caliper away from the center of the wheel. You are creating a longer lever arm which has a better mechanical advantage. Think of it as a seesaw. The further out you move from the pivot point the greater the force you apply. In this case the pivot point is the center of the hub and you have moved the point at which you are applying the force further away.

Now the other question is will it be enough to overcome the additional inertia of the heavier wheel and tire assembly?

 

now we are getting some place..

Thank You, for taking an interest in a Real .." technical question "

we have a increased radius ..

a fixed area ...

same clamping force ...

what's the Formula ..??

 

dont think you will feel a 4% difference.

You get more then that with old brake vs new brake fluid

 

That's what I was thinking - all "math" aside. Upgrade to better brake pads (Hawk DTC or Carbotech XP10/8), DOT 4 fluid (ATE or Motul) and stainless steel brake lines (Goodridge) for the OEM brakes for a lot less $$$ to achieve better results, but then again, $600 for 4% improved braking works for some people.

 

I don't need to do any calculations on such a simple radius adjustment or a Moment arm increase ( moment arm ) not leverage increase... I'M not going to go through a component analysis for such a simple question.. Oh and by the way I am not a puppet.. if you want formulas, they have this thing called the internet...do a search and do the math, if you are capable...
I gave the the answer you needed. take it or leave it.. and why would you care anyway , your the guy bragging about having Fake brake ducts.

 

we are not at 4% more ..yet ....folks ..

and are neglecting the leverage, and the thermal mass of the larger rotor .. all other factors remaining the same

I'm not looking for pads that need be warmed up, it's a street car

 

post Fact's, please

we have a 4% figure ..

where did it calculate from ..??

 

If you're not looking for pads that need to be warmed up then why do you care about the thermal mass of the larger rotors on a street car?

 

thats a valid question ...

I simply want to fill the open area on my 18" front wheel , with a larger disc

so ...

the question remains

is there a braking advantage to the larger disc, given the stock caliper area

 

I'm not a math wiz, but ET and Mark C5 said Yes. Since the bracket moves the OEM caliper further away from the center of the hub (pivot point) on the larger rotor, it provides you better mechanical advantage (longer moment arm) because you're applying the same amount of force further away from the pivot point for the torque of the rotating mass.

However, I think its negligible and you won't notice the difference. The magnitude of torque, which is also called moment or moment of force, depends on three quantities: First, the force applied; second, the length of the lever arm connecting the axis to the point of force application; and third, the angle between the two.

τ = r x F
τ = rF sinθ

where

τ is the torque vector and τ is the magnitude of the torque,
r is the displacement vector (a vector from the point from which torque is measured to the point where force is applied), and r is the length (or magnitude) of the lever arm vector,
F is the force vector, and F is the magnitude of the force,
× denotes the cross product,
θ is the angle between the force vector and the lever arm vector.
The length of the lever arm is particularly important; choosing this length appropriately lies behind the operation of levers, pulleys, gears, and most other simple machines involving a mechanical advantage.

http://en.wikipedia.org/wiki/Work_(physics)

 

now we are bearing out the original premise ..

lets solve the equation,using the Fact's we have ...

 

Have fun.

 

i have to go find my scientific calculator ....

 

This will give a 4.7% increase in brake torque to the front axle.

The difference in outer radius = (13.35" - 12.75") / 2 = .30"

Assuming the effective radius moves away radially an equal distance (not exactly true, but pretty close), a .30" improvement will increase the torque arm over the smaller rotor by about 4.7%. A full calculation would show this in error by up to .2% in either direction, based on my experience.

Swept area does not come into play in moment arm calculations, but pad shape does due to finite force distribution. As you mentioned, in this particular case it does not matter as the pad shape is not changing.

If the rears don't increase an equal amount, it is quite possible stopping distances may increase, not decrease. Moving the brake balance forward does not increase the effectiveness of all four tires UNLESS the rears were locking before the fronts without the rotor change.

The only potential gain here is thermal capacity, depending on the mass and mass distribution analysis of both the original rotor and the proposed replacement. Sorry, I'm not doing that here!

Chris

 

Yup, that 4.7% number looks about right.

I'd think any extra long term or thermal capacity would come from better cooling, but there is not enough info on those rotors to tell what the cooling difference would be. But then, if these rotors have more mass they would allow more braking before the brakes over heated. Once again, no data to know that either.

Why not just find some used C6Z51 front brakes or used brake brackets and new stock type rotors? If you want the bling, then who really cares since they won't be worse than stock.

Peter