to figure out how much gas an LS3 burns at WOT in seconds?

 

I'd like to know this about all three factory engines...?

 

I suspect many of don't care. Not planning on driving my C6 that way.

 

It is directly dependent on RPM.

All I can say is that a 1 hour track session where you're about 3/4 of the time at WOT, you'll burn about 1/2 a tank of gas... In a straight line, the faster you go, the less you seem to use because of gearing.

 

For the average person that might be hard to figure with accuracy (and I'm not talking about crunching the numbers). It would be difficult to setup a measured amount of fuel and figure consumption for a short, blast at WOT. Gearing, RPMs, etc. would also figure into the equation....is it WOT going through the gears or WOT at a certain RPM or at maximum top-end speed? Suffice it to say at WOT you're sucking-up fuel at a staggering rate. With my modified LS2 on a road course I could blow-through a tank of fuel in about six 20 minute sessions.

It's not too precise but maybe you could check the average fuel economy readout (at WOT) on the DIC.

 

Hmm ok.. I was thinking there would be an easier way to do this and I was just over-thinking it. I figured at 6.2 liter capacity engine, trying to figure out how fast it will do one entire burn of all cylinders, should be able to say something like 6.2 liters of gas in X amount of seconds

Seems there's a lot more to it. Never mind then

 

None - hits the rev limiter at WOT

 

If you'd settle for WOT at redline, then (with a little help from Google and Wikipedia) the calculation follows.

1) The Otto engine cycles are intake, compression, power, and exhaust. Gas is introduced only on the intake cycle, and there are 2 crankshaft revolutions per intake cycle, so the amount of air taken in is: (RPM / 2) x total-cylinder-volume

2) Assuming a redline of 6500 and a 6.2 engine: [(6500 revolutions / minute) / 2] x 6.2 liters = 20,150 liters / minute of air

3) Now we need to get from liters of air to gallons of gasoline. In these engines the stoichiometric ratio (molecules-of-air / molecules-of-gasoline) is 14.7, but at WOT LS3's make maximum power with tolerable combustion temperatures at lambda of less than 1.0 (i.e. rich), so assume the ratio at WOT is 13.0.

4) I'm way too lazy to figure out the conversion based on moles and molecular weights and stuff, but according to Yahoo!Answers (http://answers.yahoo.com/question/in...5194322AADsoFi)
at stoic it takes 33,300 liters of air to burn 1 gal of gasoline. So at 13.0 it would take 33,300 x (13.0 / 14.7) = 29,450 liters.

Almost there! From 2) we found that our engine is combusting 20,150 liters / minute of air. And from 4) this would be (20,150 / 29,450) x 1 gallon = 0.684.

So at WOT at redline an LS3 burns 0.684 gallons of gas per minute, or 0.114 gallon per second. At 180 mph this would be a little over 4 mpg.

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As noted in later posts, make that 0.0114 gallon per second.

 

Good work, but I think the math is off a little. 0.114 * 60 = 6.84, not .684

 

I can tell you that it gets just over 10 mpg averaging 150 mph for 60 miles from a standing start when in 5th gear with A6 trans.

And yes, that was done legally. Except for the start the lowest speed was ~130 and the highest ~165. Average was almost dead on 150.

 

^ sounds like the Silver State Classic to me...

 

Close. BBORR.

 

Math is WAY off..
..at .114 gallons per second, you'd burn through a gallon in less than 10 seconds...

..I don't think you could even pour a gallon of milk out of a milk jug in 10 seconds.

 

Here's an interesting demo of some real fuel usage...

 

as previously stated.......BORING

 

I dunno!!

Butt....I do know that when tracking my almost stock (only have a Killer Bee intake and a tune) Z06 that I get about 5-1/2 mpg.

Bob

 

GM ran the C5Z at WOT through a tank of gas during durability testing. As I recall it took about an hour to run the tank empty.

 

last time I did math 0.684/60 = 0.0114 Gal per second. @ 180 MPH in 6th gear, The motor would not be turning at 6500 rpm so a small increase in fuel economy may be seen, However, I would bet it would not be worth arguing about!! Good job on all the rest of the homework !!

 

Google agrees with ya.... HERE

 

Good catch, folks. Math-wise, 0.684 gallons of gas per minute and a little over 4 mpg at 180 mph are correct. The OP asked the question in terms of how much it burns per second, which should have been .0114 gallon per second.