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Old Aug 2, 2010 | 10:43 PM
  #1  
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Default What is this box?

I'm looking to put an HEI in my 71. I'm new to working with cars and this will be my first project of any significance. I've read all the forum posts I can find, but don't see anything about this:



It's mounted close to the firewall on the passenger side of my wiper motor. The wires lead to the distributor, coil, and carburetor (Edelbrock Performer elec. choke).

The writing reads:
CP-50B DALE
.8 ohm 10% 9824

Is this just a resistor?

Thanks.
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Old Aug 2, 2010 | 10:47 PM
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Thats the ballast resistor for the coil on your ignition. It limits the electrical current fed to the coil to keep it from burning up
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Old Aug 2, 2010 | 10:48 PM
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Thanks much!
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Old Aug 2, 2010 | 10:50 PM
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Welcome
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Old Aug 2, 2010 | 10:52 PM
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I'm guessing the wires to the coil and choke connect on the right and the distributor is the one on the left? Looks to me like the resistor for your points. It's purpose is the limit voltage to the points after cranking to make them live longer.
Hope this helps,
Jeff

EDIT:
Wasn't trying to argue, SIX posted while I was typing my response.

Last edited by True Blue Vette; Aug 2, 2010 at 10:54 PM.
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Old Aug 3, 2010 | 08:46 AM
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It's a ballast resistor alright, but my question is what's it doing in a 71? 1967 was the last year GM used a resistor. Obviously it was added by a previous owner, but I wonder why.
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Old Aug 3, 2010 | 09:15 AM
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Originally Posted by True Blue Vette
I'm guessing the wires to the coil and choke connect on the right and the distributor is the one on the left? Looks to me like the resistor for your points. It's purpose is the limit voltage to the points after cranking to make them live longer.
Hope this helps,
Jeff

EDIT:
Wasn't trying to argue, SIX posted while I was typing my response.
It limits the current, not the voltage.
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Old Aug 3, 2010 | 09:27 AM
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Originally Posted by gbvette62
It's a ballast resistor alright, but my question is what's it doing in a 71? 1967 was the last year GM used a resistor. Obviously it was added by a previous owner, but I wonder why.

Wonder what happened to the original resistor wire?
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Old Aug 3, 2010 | 10:31 AM
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Maybe there was a Pertronix in it at one time (requires no ballast) and a PO pulled the resistor wire. Who knows why these cars are put together like they are [after 40 years of 'Bubba']?
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Old Aug 3, 2010 | 11:00 AM
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Originally Posted by 69427
It limits the current, not the voltage.


but if you are installing an HEI you will not need it.
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Old Aug 3, 2010 | 11:14 AM
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Originally Posted by pauldana


but if you are installing an HEI you will not need it.
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Old Aug 3, 2010 | 08:15 PM
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OK awesome thank you. That was going to be my next question.
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Old Aug 4, 2010 | 02:45 AM
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Originally Posted by 69427
It limits the current, not the voltage.
A resistor reduces both. Aren't you an EE? WTF, you should know better than that.
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Old Aug 4, 2010 | 10:07 AM
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Originally Posted by turtlevette
A resistor reduces both. Aren't you an EE? WTF, you should know better than that.
I'm not only a EE, but an ignition and ECM/PCM designer. In the real world! I don't just play one on TV or on car forums.

The poster said the (ballast) resistor's purpose was to limit the voltage to the points. That is wrong! Anybody that states that is wrong, including you Turdle. The points are subjected to 12 volts between every dwell period. Every one! Additionally, if 12 volts was such a scary thing, how would the points survive the several hundred volts they see at the end of every dwell period? (I know the answer, but I don't feel like typing it all out.)

The ballast resistor's sole purpose is to limit the peak primary current. Additionally, the voltage at the points during dwell is ZERO, whether there's a ballast in the system or not. You're a EE too, so I assume you have a 'scope at home where you can verify this yourself.

If you have some concerns about my proficiency regarding ignition design and operation, I'm happy to discuss the formulas we use for calculating the coil primary current, risetime, energy storage, and the resulting voltage drop across the ballast (in antique systems) due to current flow if you wish. Remember, to get a voltage drop there has to be a higher "rail" voltage to begin with. In the case of the points and coil, that rail voltage is 12.

I'm tired of typing.
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Old Aug 4, 2010 | 10:17 AM
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Originally Posted by 69427
I'm not only a EE, but an ignition and ECM/PCM designer. In the real world! I don't just play one on TV or on car forums.

The poster said the (ballast) resistor's purpose was to limit the voltage to the points. That is wrong! Anybody that states that is wrong, including you Turdle. The points are subjected to 12 volts between every dwell period. Every one! Additionally, if 12 volts was such a scary thing, how would the points survive the several hundred volts they see at the end of every dwell period? (I know the answer, but I don't feel like typing it all out.)

The ballast resistor's sole purpose is to limit the peak primary current. Additionally, the voltage at the points during dwell is ZERO, whether there's a ballast in the system or not. You're a EE too, so I assume you have a 'scope at home where you can verify this yourself.

If you have some concerns about my proficiency regarding ignition design and operation, I'm happy to discuss the formulas we use for calculating the coil primary current, risetime, energy storage, and the resulting voltage drop across the ballast (in antique systems) due to current flow if you wish. Remember, to get a voltage drop there has to be a higher "rail" voltage to begin with. In the case of the points and coil, that rail voltage is 12.

I'm tired of typing.
yea... he's right, sometimes you can misinterpret things, we had a go-around about this before and I misinterpreted 69427 (still want to know what the number stands for) but yes it is used to limit current, and it does that by making a voltage divider, so yes you will see a lower voltage on the demand side of the resistor when the points are closed. hope that clears it up a bit.... and im an EE also
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Old Aug 4, 2010 | 03:37 PM
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Originally Posted by pauldana
yea... he's right, sometimes you can misinterpret things, we had a go-around about this before and I misinterpreted 69427 (still want to know what the number stands for) but yes it is used to limit current, and it does that by making a voltage divider, so yes you will see a lower voltage on the demand side of the resistor when the points are closed. hope that clears it up a bit.... and im an EE also
Car in background ('69), and current street/track engine being used to mockup my replacement run-in/break-in stand. (I sold my previous stand when I moved a couple years ago, and apparently the guy likes it 'cuz he won't sell it back to me now that I need one again.)



New track engine (under construction). Hoping to get it into the car later this month.

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Old Aug 4, 2010 | 06:05 PM
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Originally Posted by 69427
New track engine (under construction). Hoping to get it into the car later this month.

very very nice this one.... wow... i would love to build a 427.....
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Old Aug 5, 2010 | 01:45 PM
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Originally Posted by 69427
I'm not only a EE, but an ignition and ECM/PCM designer. In the real world! I don't just play one on TV or on car forums.

The poster said the (ballast) resistor's purpose was to limit the voltage to the points. That is wrong! Anybody that states that is wrong, including you Turdle. The points are subjected to 12 volts between every dwell period. Every one! Additionally, if 12 volts was such a scary thing, how would the points survive the several hundred volts they see at the end of every dwell period? (I know the answer, but I don't feel like typing it all out.)

The ballast resistor's sole purpose is to limit the peak primary current. Additionally, the voltage at the points during dwell is ZERO, whether there's a ballast in the system or not. You're a EE too, so I assume you have a 'scope at home where you can verify this yourself.

If you have some concerns about my proficiency regarding ignition design and operation, I'm happy to discuss the formulas we use for calculating the coil primary current, risetime, energy storage, and the resulting voltage drop across the ballast (in antique systems) due to current flow if you wish. Remember, to get a voltage drop there has to be a higher "rail" voltage to begin with. In the case of the points and coil, that rail voltage is 12.

I'm tired of typing.
The resistor is there so you won't overheat the points or rundown the battery if the ignition key is left on and they happen to be closed. Electronic ignitions provide a rising edge trigger so they are not a concern. I would think that it could be taken out and full voltage applied as a no cost performance boost. That would allow the coil to charge quicker and provide a hotter spark. Just don't leave the key in the run position for any length of time with the engine off.

Or am i full of crap?

Last edited by turtlevette; Aug 5, 2010 at 01:49 PM.
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Old Aug 5, 2010 | 01:55 PM
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That's beautiful !!!
Originally Posted by 69427
New track engine (under construction). Hoping to get it into the car later this month.
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Old Aug 5, 2010 | 02:36 PM
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Originally Posted by turtlevette
The resistor is there so you won't overheat the points or rundown the battery if the ignition key is left on and they happen to be closed. You'll still run the battery down even with the ballast in there. The primary circuit series resistance (not impedance, because the engine isn't running at the moment) means there's going to be about 4 amps of current drain if you leave the key on with the points closed. Regarding burning the points, I don't know, that's debatable. I haven't run points since I converted my '69 in 1974 (pre-HEI), but I was under the impression that the actual contacts were made of tungsten, which is a high temperature capable material. If there's 4 amps draining in the system, and the points are 1 Ohm, then there's 16 watts. (New points with O ohms would obviously be O watts.) The points would obviously get very warm, but that level of wattage doesn't seem significant given the efficient heat sink (breaker plate) that the points are screwed/fastened to. But, having minimal time experience with points in my car, I would have to defer to the comments/experiences of those with points and frequent incidences of the key being on while the engine is stopped. Electronic ignitions provide a rising edge trigger so they are not a concern. Sophisticated electronic systems do. It's my understanding that some Hall Effect type conversions are just dumb switches that have the same waveform as a set of points, and associated issues when the key is left on. I would think that it could be taken out and full voltage applied as a no cost performance boost. That would allow the coil to charge quicker and provide a hotter spark. Just don't leave the key in the run position for any length of time with the engine off.

Or am i full of crap?
On most things, that's a resounding Yes.

But, your last comment has merit. I've mentioned to previous posters that for drag race use it's possible to have a toggle switch wired between the fuse box and the coil + terminal. Switching out/bypassing the ballast resistor during high RPM situations allows the coil to charge much quicker, resulting in more coil/spark energy. (Of course, a toggle switch doesn't have the bling factor of a red machined aluminum box, though. )
Just remember to open the switch on the cool down drive back to the pits.
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