C4 Tech/Performance L98 Corvette and LT1 Corvette Technical Info, Internal Engine, External Engine

Can someone check my math???

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Old Dec 5, 2003 | 12:42 PM
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Default Can someone check my math???

http://forums.corvetteforum.com/zerothread?id=704446

Sorry, should have posted here first. :cheers:
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Old Dec 5, 2003 | 06:51 PM
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Default Re: Can someone check my math??? (mn_vette)

TTT for the evening crew
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Old Dec 5, 2003 | 08:56 PM
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Default Re: Can someone check my math??? (mn_vette)

http://forums.corvetteforum.com/zerothread?id=704446

Sorry, should have posted here first. :cheers:
Isn't that formula backwards? Been a long time since I've seen it, but isn't it written the other way 'round?

Jake
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Old Dec 5, 2003 | 09:59 PM
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Default Re: Can someone check my math??? (mn_vette)

I checked your math and it is fine but I do not believe you added your N2O HP correctly to the engine HP at 3000 RPM. A 250 HP N2O kit is not going to produce 250 extra HP at 3000 RPM, it will produce the 250 HP at the engines N/A HP peak RPM point. If the the N/A hp peak occurs at 6000 RPM the N2O HP peak will also occur around 6000 RPM. The HP addition at 3000 RPM will be approximately 1/2 of the peak HP gain of 250 or approximately 125 HP.

If I use your estimate of 200 HP at 3000 RPM and then add 125 for a total of 325 HP at 3000 RPM I would end up with a torque number or 569 FT/LBS.
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Old Dec 6, 2003 | 05:10 AM
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Default Re: Can someone check my math??? (bjankuski)

Correct me if I'm wrong, but the formula is

HP= (TQxRPM)/5252

Remember, HP is a calculated value (not measured) determined by torque and rpm.

Jake
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Old Dec 6, 2003 | 01:56 PM
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Default Re: Can someone check my math??? (bjankuski)

If I use your estimate of 200 HP at 3000 RPM and then add 125 for a total of 325 HP at 3000 RPM I would end up with a torque number or 569 FT/LBS.
I hate to say it but that isn't the way nitrous works. You are adding a given amount of fuel and nitrous into the engine so no matter what the same additional work over time will be had no matter what rpm your engine is running at.

Correct me if I'm wrong, but the formula is
HP= (TQxRPM)/5252
exactly, but you can rearrange the formula using basic algebra to be

TQ = (HP * 5252)/RPM

Try out the numbers and you'll see that they work both ways.
http://vettenet.org/torquehp.html
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Old Dec 7, 2003 | 11:49 AM
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Default Re: Can someone check my math??? (mn_vette)

mn vette:
Your formula looks basically correct but I think you need to double check your unit manipulation. The formula if I can remember correctly, (my engineering reference book is at work); Power(Watts) = Torque(Radius) X [cross] Force (newtons) multiplied by Angular velocity (radians/sec). Again if I can remember correctly this formula is only valid for measurements taken using the metric system, this is where that correction factor of 5252 probably comes from but my only concern is since you don't have a unit label associated with it you don't know if it can be simply divided out as you have done. I will try to do a little more research later tonight and double check your figures.

Ethan
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Old Dec 7, 2003 | 01:09 PM
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Default Re: Can someone check my math??? (mn_vette)

Your math looks good to me; I think your estimate may indeed be a little low on HP as my 350 L98 builds 180 CHP at 3,000rpm.

The only issue I see is how that 250-shot varries across the RPM band. We can expect pumping losses to vary with RPM due to exhaust restriction, among other factors (is a 250-shot constant across the RPM band...then torque must fall off...).


[Modified by 65Z01, 1:14 PM 12/7/2003]
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