300mph C5???


I read a very interesting article on the car it's amazing the technology involved in going 250mph safely. I don't foresee a corvette with only basic steering rack set up, basic non-adjustable suspension, safely approaching anywhere near 300mph, let alone never catching up to the bugati's 250mph.

Chris


A Top Fueler makes around 6500 Hp and it weighs in at slightly over 2100. It took until 1996 to reach 300. Now I understand that this is only in 1/4 mile but look at some of the cars on the dry lakes with the same HP and weight....they reach about 230
Ironing board is only good to 192mph. You have to go to the park bench model to break 200mph....
Last edited by EG@EnglandGreen; Dec 6, 2005 at 03:23 PM.
Ahmet
The Best of Corvette for Corvette Enthusiasts
Ahmet

http://www.rbracing-rsr.com/aerohpcalc.html
It is intended for bikes, but seems to scale to 4 wheeled vehicles if the proper variables are plugged in. Here are the figures for a C5 coupe, which has the best chance of succeeding (right
), since it has better aerodynamics than the Z06:Frontal area = 21.3
Weight = 3210 + your weight *
Speed = 300
After adding in my weight, it would take over 1217rwhp to propel me to 300mph (assuming the Z-rated tires don't explode or the car become airborne first).





Slap a JATO pack on ith THEN you might have something
The power P needed to reach a speed v in a car is approximately proportional to the cube of the latter,
P ~ v^3......................(1)
With
P' ~ v'^3.....................(2)
and dividing Eq. (1) by Eq. (2) and multiplying both sides by P', we get a formula to estimate the power P needed to achieve a speed v when the car reaches a speed v' with a power P'
P = P' (v/v')^3..............(3)
Thus, with P'=350 hp, v'=175 mph, and v=300 mph, we get P=1763 hp. Moreover, we may solve Eq. (3) for v, to obtain the top speed at a given power P,
v = cube root(P/P') v'.....(4)
With P=992 hp, P'=350 hp, and v=175 mph, we get v=248 mph. Remark: I used engine powers instead of rear wheel powers. However, assuming that the losses in the drive train are proportional to the engine power, the above calculation is unchanged if we insert rear wheel powers for P and P'.
Its great to be a theoretical physicist
Bob












Euro dash gauges.... 

