200 Mph
You could theroretically put a twin turbo diesel engine in a vette
(I know)
, that has ONLY 325 rwhp and 600 ft lb of torque and still do 200 mph.The formulas used to determine a vehicle's top speed doesn't include a torque parameter, but does include a HP parameter. Torque is part of the definition of HP. Having high torque and low HP like your example is not how it works.
It all boils down to HP and gearing ... period ... (and vehicle aeros, rolling resistance, air conditions and traction).
Last edited by ZeeOSix; Jun 16, 2007 at 12:57 AM.
... it still boils down to HP. I'll bet every one of those cars going over 200 mph make more HP than required to go over 200 mph ... and are obviously geared to match the power characteristics of their motors. As said before, top speed does not depend on torque alone ... it depends on HP. For instance, you could not go 200 mph with an engine that made 5000 ft-lbs of torque at a 200 RPM redline ... no matter how it was geared.HP = (T x RPM)/5252 = (5000 x 200)/5252 = 190.4 HP
You think a 190 HP engine that produces 5000 ft-lbs of T at 200 RPM could propel a car to 200 mph? ... think about it.
The answer is no ... because if it was geared to go 200 mph the torque would be reduced significantly at the drive wheels to the point where it could only go as fast as 190 HP would ever allow it to go, regardless of how much torque the engine puts out. Remember, that it's the HP at the rear wheels (after all the gearing changes the crankshaft's torque to the drive axle torque) that's moving the car. The HP equation also applies at the rear wheels (it applies at every rotating shaft in fact), and that's where it really counts.This is how it really works.
If "Engine A" makes say 600 HP at half the RPM, but twice the torque as "Engine B" (which also makes 600 HP), then the car with "Engine A" in it could be geared to make the car go just as fast as if it had "Engine B". It's HP that is what really counts - available torque must "tuned" with gearing to match the car and it's application. Gearing matches the engine's power output to make the car accelerate and hit the highest possible top speed based on the engine's available HP.
Bottom line -- it all comes down to HP, and appropriate gearing to match the power output of the engine based on what the car is being used for.
Last edited by ZeeOSix; Jun 16, 2007 at 06:58 PM.
... it still boils down to HP. I'll bet every one of those cars going over 200 mph make more HP than required to go over 200 mph ... and are obviously geared to match the power characteristics of their motors. As said before, top speed does not depend on torque alone ... it depends on HP. For instance, you could not go 200 mph with an engine that made 5000 ft-lbs of torque at a 200 RPM redline ... no matter how it was geared.HP = (T x RPM)/5252 = (5000 x 200)/5252 = 190.4 HP
You think a 190 HP engine that produces 5000 ft-lbs of T at 200 RPM could propel a car to 200 mph? ... think about it.
The answer is no ... because if it was geared to go 200 mph the torque would be reduced significantly at the drive wheels to the point where it could only go as fast as 190 HP would ever allow it to go, regardless of how much torque the engine puts out. Remember, that it's the HP at the rear wheels (after all the gearing changes the crankshaft's torque to the drive axle torque) that's moving the car. The HP equation also applies at the rear wheels (it applies at every rotating shaft in fact), and that's where it really counts.This is how it really works.
If "Engine A" makes say 600 HP at half the RPM, but twice the torque as "Engine B" (which also makes 600 HP), then the car with "Engine A" in it could be geared to make the car go just as fast as if it had "Engine B". It's HP that is what really counts - available torque must "tuned" with gearing to match the car and it's application. Gearing matches the engine's power output to make the car accelerate and hit the highest possible top speed based on the engine's available HP.
Bottom line -- it all comes down to HP, and appropriate gearing to match the power output of the engine based on what the car is being used for.
I NEVER said that horsepower was not part of the equation, go take your medication

You claimed those diesels "probably have a low rpm redline and do not develop as much HP as other cars in their class", but yet can go well over 200 mph.
Well, the reason for that is because they still make more than enough HP to go over 200 mph, regardless of how much torque they make.
Just trying to clarify your cryptic statements so others knew what was going on.
Last edited by ZeeOSix; Jun 16, 2007 at 07:32 PM.

You claimed those diesels "probably have a low rpm redline and do not develop as much HP as other cars in their class", but yet can go well over 200 mph.
Well, the reason for that is because they still make more than enough HP to go over 200 mph, regardless of how much torque they make.
Just trying to clarify your cryptic statements .
http://en.wikipedia.org/wiki/Audi_R10
I have NEVER contradicted ANY of your posts Junior, as a matter of fact I have NEVER contradicted ANYBODY's posts. The only point of my post was to make mention that mph goals could be acheived with several variables, but the bottom line is that any vehicle needs HP & TQ to attain and maintain a given speed
The Best of Corvette for Corvette Enthusiasts
http://en.wikipedia.org/wiki/Audi_R10
I have NEVER contradicted ANY of your posts Junior, as a matter of fact I have NEVER contradicted ANYBODY's posts. The only point of my post was to make mention that mph goals could be acheived with several variables, but the bottom line is that any vehicle needs HP & TQ to attain and maintain a given speed
Last edited by ZeeOSix; Jun 16, 2007 at 07:47 PM.
You two get together & play spin the bottle
ez = 1 + z + z2/2! + z3/3! + z4/4! + z5/5! + z6/6! + Torque ... ,
cos(z) = 1 - z2/2! + z4/4! - z6/6! + z8/8! - z10/10! + Horsepower ... ,
sin(z) = z - z3/3! + z5/5! - z7/7! + z9/9! - z11/11! + drag... .
All three series are valid for all real numbers. We want to accept the first one as valid for all complex numbers z. Then substitute z = xi, expand, use the facts that i2 = -1, i3 = -i, i4 = 1, and so on, and collect real and imaginary parts. You'll see that the real part of exi is just the series for cos(x), and the imaginary part is just the series for sin(x).
z = cos(x) + sin(x) i
and notice that when x = 0, z = 1. Then differentiate,
dz/dx = -sin(x) + cos(x) i
dz/dx = sin(x) i2 + cos(x) i
dz/dx = [cos(x) + sin(x) i]i
dz/dx = zi
(1/z)dz/dx = i
ln(z) = xi + C
for some constant C, by indefinite integration. Now use the fact that when x = 0, z = 1, to conclude that C = 0. Thus
ln(z) = xi
z = exi
exi = cos(x) + sin(x) i
|z| = sqrt(a2+b2)
z/|z| is then a complex number whose absolute value is 1. Then there is some t such that
cos(t) = a/sqrt(a2+b2)
sin(t) = b/sqrt(a2+b2)
tan(t) = b/a,
t = arctan(b/a)
You can always choose t in the range 0 <= t < 2 to satisfy these conditions. There are two t values in this range with tangent b/a, which differ by . Pick t > if and only if b < 0. Pick t = if and only if b = 0 and a < 0. Then
z = sqrt(a2+b2)[a/sqrt(a2+b2) + bi/sqrt(a2+b2)]
= sqrt(a2+b2)[cos(t) + sin(t) i]
= |z|eti
= eln|z|+ti
Last edited by David426; Jun 17, 2007 at 06:26 AM.












